Optimal. Leaf size=86 \[ -\frac{\text{PolyLog}\left (2,1-\frac{2 (a+b x)}{(x+1) (a+b)}\right )}{2 b}+\frac{\text{PolyLog}\left (2,1-\frac{2}{x+1}\right )}{2 b}+\frac{\tanh ^{-1}(x) \log \left (\frac{2 (a+b x)}{(x+1) (a+b)}\right )}{b}-\frac{\log \left (\frac{2}{x+1}\right ) \tanh ^{-1}(x)}{b} \]
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Rubi [A] time = 0.0608797, antiderivative size = 86, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.4, Rules used = {5920, 2402, 2315, 2447} \[ -\frac{\text{PolyLog}\left (2,1-\frac{2 (a+b x)}{(x+1) (a+b)}\right )}{2 b}+\frac{\text{PolyLog}\left (2,1-\frac{2}{x+1}\right )}{2 b}+\frac{\tanh ^{-1}(x) \log \left (\frac{2 (a+b x)}{(x+1) (a+b)}\right )}{b}-\frac{\log \left (\frac{2}{x+1}\right ) \tanh ^{-1}(x)}{b} \]
Antiderivative was successfully verified.
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Rule 5920
Rule 2402
Rule 2315
Rule 2447
Rubi steps
\begin{align*} \int \frac{\tanh ^{-1}(x)}{a+b x} \, dx &=-\frac{\tanh ^{-1}(x) \log \left (\frac{2}{1+x}\right )}{b}+\frac{\tanh ^{-1}(x) \log \left (\frac{2 (a+b x)}{(a+b) (1+x)}\right )}{b}+\frac{\int \frac{\log \left (\frac{2}{1+x}\right )}{1-x^2} \, dx}{b}-\frac{\int \frac{\log \left (\frac{2 (a+b x)}{(a+b) (1+x)}\right )}{1-x^2} \, dx}{b}\\ &=-\frac{\tanh ^{-1}(x) \log \left (\frac{2}{1+x}\right )}{b}+\frac{\tanh ^{-1}(x) \log \left (\frac{2 (a+b x)}{(a+b) (1+x)}\right )}{b}-\frac{\text{Li}_2\left (1-\frac{2 (a+b x)}{(a+b) (1+x)}\right )}{2 b}+\frac{\operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+x}\right )}{b}\\ &=-\frac{\tanh ^{-1}(x) \log \left (\frac{2}{1+x}\right )}{b}+\frac{\tanh ^{-1}(x) \log \left (\frac{2 (a+b x)}{(a+b) (1+x)}\right )}{b}+\frac{\text{Li}_2\left (1-\frac{2}{1+x}\right )}{2 b}-\frac{\text{Li}_2\left (1-\frac{2 (a+b x)}{(a+b) (1+x)}\right )}{2 b}\\ \end{align*}
Mathematica [C] time = 0.0845367, size = 260, normalized size = 3.02 \[ \frac{-4 \text{PolyLog}\left (2,e^{-2 \left (\tanh ^{-1}\left (\frac{a}{b}\right )+\tanh ^{-1}(x)\right )}\right )-4 \text{PolyLog}\left (2,-e^{2 \tanh ^{-1}(x)}\right )+8 \tanh ^{-1}(x) \tanh ^{-1}\left (\frac{a}{b}\right )+8 \tanh ^{-1}\left (\frac{a}{b}\right ) \log \left (1-e^{-2 \left (\tanh ^{-1}\left (\frac{a}{b}\right )+\tanh ^{-1}(x)\right )}\right )+8 \tanh ^{-1}(x) \log \left (1-e^{-2 \left (\tanh ^{-1}\left (\frac{a}{b}\right )+\tanh ^{-1}(x)\right )}\right )-8 \tanh ^{-1}\left (\frac{a}{b}\right ) \log \left (2 i \sinh \left (\tanh ^{-1}\left (\frac{a}{b}\right )+\tanh ^{-1}(x)\right )\right )+8 \tanh ^{-1}(x) \log \left (i \sinh \left (\tanh ^{-1}\left (\frac{a}{b}\right )+\tanh ^{-1}(x)\right )\right )-8 \tanh ^{-1}(x) \log \left (2 i \sinh \left (\tanh ^{-1}\left (\frac{a}{b}\right )+\tanh ^{-1}(x)\right )\right )+4 \tanh ^{-1}\left (\frac{a}{b}\right )^2+4 i \pi \log \left (\frac{2}{\sqrt{1-x^2}}\right )+8 \log \left (\frac{2}{\sqrt{1-x^2}}\right ) \tanh ^{-1}(x)+4 \log \left (1-x^2\right ) \tanh ^{-1}(x)+8 \tanh ^{-1}(x)^2+4 i \pi \tanh ^{-1}(x)-8 \tanh ^{-1}(x) \log \left (e^{2 \tanh ^{-1}(x)}+1\right )-4 i \pi \log \left (e^{2 \tanh ^{-1}(x)}+1\right )-\pi ^2}{8 b} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.11, size = 110, normalized size = 1.3 \begin{align*}{\frac{\ln \left ( bx+a \right ){\it Artanh} \left ( x \right ) }{b}}+{\frac{\ln \left ( bx+a \right ) }{2\,b}\ln \left ({\frac{bx-b}{-a-b}} \right ) }+{\frac{1}{2\,b}{\it dilog} \left ({\frac{bx-b}{-a-b}} \right ) }-{\frac{\ln \left ( bx+a \right ) }{2\,b}\ln \left ({\frac{bx+b}{-a+b}} \right ) }-{\frac{1}{2\,b}{\it dilog} \left ({\frac{bx+b}{-a+b}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.974155, size = 161, normalized size = 1.87 \begin{align*} -\frac{{\left (\log \left (x + 1\right ) - \log \left (x - 1\right )\right )} \log \left (b x + a\right )}{2 \, b} + \frac{\operatorname{artanh}\left (x\right ) \log \left (b x + a\right )}{b} - \frac{\log \left (x - 1\right ) \log \left (\frac{b x - b}{a + b} + 1\right ) +{\rm Li}_2\left (-\frac{b x - b}{a + b}\right )}{2 \, b} + \frac{\log \left (x + 1\right ) \log \left (\frac{b x + b}{a - b} + 1\right ) +{\rm Li}_2\left (-\frac{b x + b}{a - b}\right )}{2 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{artanh}\left (x\right )}{b x + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{atanh}{\left (x \right )}}{a + b x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{artanh}\left (x\right )}{b x + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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